JEE Main 2023ChemistryIonic EquilibriumHardNumerical

JEE Main 2023 — Ionic Equilibrium Question with Solution

JEE Main 2023 (30 Jan Shift 1)

Question

600mL of 0.01M HCl is mixed with 400mL of 0.01M H2SO4. The pH of the mixture is _____×10-2. (Nearest integer)

[Given log2=0.30,   log3=0.48,  log5=0.69,   log7=0.84,   log11=1.04]

Enter your answer

Show full solutionCorrect answer: 186
Correct answer
186

Step-by-step explanation

The number of millimoles = Molarity ×  Volume in mL

HCl produce one and H2SO4 produce two H+ ions respectively.

Total milimoles of H+=600×0.01+400×0.01×2=14
Thus, moles of hydrogen ion:
⇒H+=141000=14×10-3
⇒pH = -log[H+]=-log[14 × 10-3]

⇒pH=3-log14

=1.86

=186×10-2

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About this question

This is a previous-year question from JEE Main 2023, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.