JEE Main 2019 — Haloalkanes And Haloarenes Question with Solution
From: JEE Main 2019 (Online) 12th January Evening Slot
Question
The major product in the following conversion is –
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
As here HBr is present in excess, so HBr will react to alkene and ether part sinultaneously.
According to Markovnikov rule. Carbocation close to benzene ring is more stable.
In the given reagent, carbocation is
So in HBr, Br adds to the carbocation.
And in the ether part because of lone pair of oxygen, it will take part in resonance a double bond will create between O atom and benzene ring. So, this bond will be stronger. That is why CH3 O bond will break.
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This is a previous-year question from JEE Main 2019, covering the Haloalkanes And Haloarenes chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.