JEE Main 2023 — Haloalkanes and Haloarenes Question with Solution
JEE Main 2023 (13 Apr Shift 2)
Question
Match List-I with List-II.
1-Bromopropane is reacted with reagents in List-I to give product in List-II
| List-I Reagent | List-II Product | ||
| A. | KOH (alc) | I. | Nitrile |
| B. | KCN (alc) | II. | Ester |
| C. | AgNO2 | III. | Alkene |
| D | H3CCOOAg | IV. | Nitroalkane |
Choose an option
Show full solutionCorrect option: A
Step-by-step explanation
(A) When bromopropane reacts with alcoholic, the bromine with the alpha H (hydrogen from the carbon alongside the carbon fortified with useful gathering) is eliminated and subsequently forms propene. 
(B) When Bromo propane reacts with it will form butanenitrile.
(C) When akyl halide reacts with silver nitrite, nitroalkane is formed because the bond between is covalent, the lone pair on nitrogen acts as an attacking site for nucleophilic substitution. 
(D) When bromopropane reacts with silver acetate, propyl ethanoate and silver bromide are formed.
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This is a previous-year question from JEE Main 2023, covering the Haloalkanes and Haloarenes chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.