JEE Main 2018 — General Organic Chemistry Question with Solution
JEE Main 2018 (15 Apr Shift 1 Online)
Question
The correct match between items of List-I and List-II is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C(A)-(r), (B)-(p), (C)-(q), (D)-(s)
Step-by-step explanation
(a) Charcoal treatment removes coloured impurity through adsorption.
(b) Steam distillation separates the mixture of -nitrophenol and -nitrophenol. The -nitrophenol is steam volatile (due to intramolecular hydrogen bonding), and the para isomer is not volatile.
(c) Fractional distillation separates crude naphtha. Naphtha is a flammable liquid hydrocarbon mixture.
(d) Distillation under reduced pressure separates mixture of glycerol and sugars. Vacuum distillation lowers the boiling point and prevents decomposition.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the General Organic Chemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2018, covering the General Organic Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.