JEE Main 2015ChemistryGeneral Organic ChemistryMediumMCQ

JEE Main 2015 — General Organic Chemistry Question with Solution

JEE Main 2015 (04 Apr)

Question

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg AgBr. What is the percentage of bromine in the compound (atomic mass of Ag=108 and atomic number of Br=80)?

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Show full solutionCorrect option: B
Correct answer
B24

Step-by-step explanation

R - Br → Carius method AgBr

250 mg organic compound is RBr.

141 mgAgBr⇒141×80188mgBr
From principle of atom coservation(POAC), mass of Bromine is conserved in reactant and product

So, mass of Bromine in organic compound = 141×80188 mg

% of Br in organic compound = mass of Brmass of compound×100

=141×80188×1250×100=24%

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About this question

This is a previous-year question from JEE Main 2015, covering the General Organic Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.