JEE Main 2019 — Electrochemistry Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
Given
CO3+ + e– CO2+ ; Eo = + 1.81 V
Pb4+ + 2e– Pb2+ ; Eo = + 1.67 V
Ce4+ + e– Ce3+ ; Eo = + 1.61 V
Bi3+ + 3e– Bi ; Eo = + 0.20 V
Oxidizing power of the species will increase in the order :
CO3+ + e– CO2+ ; Eo = + 1.81 V
Pb4+ + 2e– Pb2+ ; Eo = + 1.67 V
Ce4+ + e– Ce3+ ; Eo = + 1.61 V
Bi3+ + 3e– Bi ; Eo = + 0.20 V
Oxidizing power of the species will increase in the order :
Choose an option
Show full solutionCorrect option: D
Correct answer
DBi3+ < Ce4+
< Pb4+ < Co3+
Step-by-step explanation
Higher the value of Standard reduction potential of metal ion electrode, the more strong oxidizing agent is that metal ion electrode and have greater oxidising power.
So, Bi3+ < Ce4+ < Pb4+ < Co3+
So, Bi3+ < Ce4+ < Pb4+ < Co3+
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