JEE Main 2017 — Electrochemistry Question with Solution
From: JEE Main 2017 (Online) 9th April Morning Slot
Question
To find the standard potential of M3+/M electrode,the following cell is constituted : Pt/M/M3+(0.001 mol L−1 )/Ag+(0.01 mol L−1 )/Ag
The emf of the cell is found to be 0.421 volt at 298 K. The standard potential of half reaction M3+ + 3e− M at 298 K will be :
(Given at 298 K = 0.80 Volt)
The emf of the cell is found to be 0.421 volt at 298 K. The standard potential of half reaction M3+ + 3e− M at 298 K will be :
(Given at 298 K = 0.80 Volt)
Choose an option
Show full solutionCorrect option: B
Correct answer
B0.32 Volt
Step-by-step explanation
According to Nernst equation, for the cell reaction
M(s) + 3Ag+(aq) M3+(aq) + 3Ag(s)
Substituting the values, we get
We know that
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