JEE Main 2021 — Electrochemistry Question with Solution
From: JEE Main 2021 (Online) 18th March Morning Shift
Question
For the reaction
2Fe3+(aq) + 2I(aq) 2Fe2+(aq) + I2(s)
the magnitude of the standard molar Gibbs free energy change, rG = ___________ kJ (Round off to the Nearest Integer).
\left[ {\matrix{ {E_{F{e^{2 + }}/Fe(s)}^o = - 0.440V;} & {E_{F{e^{3 + }}/Fe(s)}^o = - 0.036V} \cr {E_{{I_2}/2{I^ - }}^o = 0.539V;} & {F = 96500C} \cr } } \right]
2Fe3+(aq) + 2I(aq) 2Fe2+(aq) + I2(s)
the magnitude of the standard molar Gibbs free energy change, rG = ___________ kJ (Round off to the Nearest Integer).
\left[ {\matrix{ {E_{F{e^{2 + }}/Fe(s)}^o = - 0.440V;} & {E_{F{e^{3 + }}/Fe(s)}^o = - 0.036V} \cr {E_{{I_2}/2{I^ - }}^o = 0.539V;} & {F = 96500C} \cr } } \right]
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