JEE Main 2019 — Electrochemistry Question with Solution
From: JEE Main 2019 (Online) 10th January Morning Slot
Question
Consider the following reduction processes :
Zn2+ + 2e– Zn(s) ; Eo = – 0.76 V
Ca2+ + 2e– Ca(s); Eo = –2.87 V
Mg2+ + 2e– Mg(s) ; Eo = – 2.36 V
Ni2 + 2e– Ni(s) ; Eo = – 0.25
The reducing power of the metals increases in the order :
Zn2+ + 2e– Zn(s) ; Eo = – 0.76 V
Ca2+ + 2e– Ca(s); Eo = –2.87 V
Mg2+ + 2e– Mg(s) ; Eo = – 2.36 V
Ni2 + 2e– Ni(s) ; Eo = – 0.25
The reducing power of the metals increases in the order :
Choose an option
Show full solutionCorrect option: B
Correct answer
BNi < Zn < Mg < Ca
Step-by-step explanation
Higher the oxidation potential better will be reducing power.
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This is a previous-year question from JEE Main 2019, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.