JEE Main 2023 — Electrochemistry Question with Solution
From: JEE Main 2023 (Online) 10th April Morning Shift
Question
\mathrm{FeO_4^{2 - }\buildrel { + 2.2V} \over \longrightarrow F{e^{3 + }}\buildrel { + 0.70V} \over \longrightarrow F{e^{2 + }}\buildrel { - 0.45V} \over \longrightarrow F{e^0}}
is V. The value of is _________
Enter your answer
Show full solutionCorrect answer: 1825
Correct answer
1825
Step-by-step explanation
Hence for
electron exchange of that half cell reaction.
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This is a previous-year question from JEE Main 2023, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.