JEE Main 2022 — Electrochemistry Question with Solution

Resistance of a conductivity cell (cell constant $$129{\mathrm{m}}^{-1}$$) filled with $$74.5\mathrm{ppm}$$ solution of $$\mathrm{KCl}$$ is $$100\Omega$$ (labelled as solution 1). When the same cell is filled with $$\mathrm{KCl}$$ solution of $$149\mathrm{ppm}$$, the resistance is $$50\Omega$$ (labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. $$\frac{{\wedge }_1}{{\wedge }_2}=x\times 10^{-3}$$. The value of $$x$$ is __________. (Nearest integer)

Given, molar mass of $$\mathrm{KCl}$$ is $$74.5\mathrm{g}{\mathrm{mol}}^{-1}$$.