JEE Main 2021 — Electrochemistry Question with Solution
From: JEE Main 2021 (Online) 27th July Evening Shift
Question
For the cell
Cu(s) | Cu2+ (aq) (0.1 M) || Ag+(aq) (0.01 M) | Ag(s)
the cell potential E1 = 0.3095 V
For the cell
Cu(s) | Cu2+ (aq) (0.01 M) || Ag+(aq) (0.001 M) | Ag(s)
the cell potential = ____________ 102 V. (Round off the nearest integer).
[Use : = 0.059]
Cu(s) | Cu2+ (aq) (0.1 M) || Ag+(aq) (0.01 M) | Ag(s)
the cell potential E1 = 0.3095 V
For the cell
Cu(s) | Cu2+ (aq) (0.01 M) || Ag+(aq) (0.001 M) | Ag(s)
the cell potential = ____________ 102 V. (Round off the nearest integer).
[Use : = 0.059]
Enter your answer
Show full solutionCorrect answer: 28
Correct answer
28
Step-by-step explanation
Cell reaction is :
Now, .... (1)
....(2)
From (1) and (2), E2 = 0.28 V = 28 102 V
Now, .... (1)
....(2)
From (1) and (2), E2 = 0.28 V = 28 102 V
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This is a previous-year question from JEE Main 2021, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.