JEE Main 2020 — Electrochemistry Question with Solution
From: JEE Main 2020 (Online) 6th September Morning Slot
Question
Potassium chlorate is prepared by the
electrolysis of KCl in basic solution
6OH- + Cl- ClO3- + 3H2O + 6e-
If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO3 using a current of 2 A is_________.
(Given : F = 96,500 C mol–1; molar mass of KCIO3 = 122 g mol–1)
6OH- + Cl- ClO3- + 3H2O + 6e-
If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO3 using a current of 2 A is_________.
(Given : F = 96,500 C mol–1; molar mass of KCIO3 = 122 g mol–1)
Enter your answer
Show full solutionCorrect answer: 10.98
Correct answer
10.98
Step-by-step explanation
For synthesis of 1 mole of ClO3- , 6F of charge
is required.
To synthesise moles of KClO3,
Charge required = F
t(hr) = = 10.98 hr 11 Hr
To synthesise moles of KClO3,
Charge required = F
t(hr) = = 10.98 hr 11 Hr
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