JEE Main 2020 — Coordination Compounds Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
For octahedral Mn(II) and tetrahedral Ni(II)
complexes, consider the following statements:
(I) both the complexes can be high spin.
(II) Ni(II) complex can very rarely be low spin.
(III) with strong field ligands, Mn(II) complexes can be low spin.
(IV)aqueous solution of Mn(II) ions is yellow in colour.
The correct statements are :
(I) both the complexes can be high spin.
(II) Ni(II) complex can very rarely be low spin.
(III) with strong field ligands, Mn(II) complexes can be low spin.
(IV)aqueous solution of Mn(II) ions is yellow in colour.
The correct statements are :
Choose an option
Show full solutionCorrect option: D
Correct answer
D(I), (II) and (III) only
Step-by-step explanation
(I) Under weak field ligand, octahedral Mn(II) and tetrahedral Ni(II) both the complexes are high spin
complex.
(II) Tetrahedral Ni(II) complex can very rarely be low spin because square planar (under strong ligand) complexes of Ni(II) are low spin complexes.
(III)With strong field ligands Mn (II) complexes can be low spin because they have less number of unpaired electron (unpaired electron = 1) While with weak field ligands Mn(II) complexes can be high spin because they have more number of unpaired electron (unpaired electron = 5)
(IV) Aqueous solution of Mn(II) ions is pink in colour.
(II) Tetrahedral Ni(II) complex can very rarely be low spin because square planar (under strong ligand) complexes of Ni(II) are low spin complexes.
(III)With strong field ligands Mn (II) complexes can be low spin because they have less number of unpaired electron (unpaired electron = 1) While with weak field ligands Mn(II) complexes can be high spin because they have more number of unpaired electron (unpaired electron = 5)
(IV) Aqueous solution of Mn(II) ions is pink in colour.
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