JEE Main 2025 — Coordination Compounds Question with Solution

In ${\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right]}_6\right]}^{3+},{\mathrm{Co}}^{+3}:[\mathrm{Ar}]3{\mathrm{d}}^6,{\mathrm{NH}}_3$ is S.F.L

Hybridisation state of ${\mathrm{Co}}^{3+}$ is ${\mathrm{d}}^2{\mathrm{sp}}^3$

In ${\mathrm{SF}}_6$, Hybridisation state of sulphur is ${\mathrm{sp}}^3{\mathrm{d}}^2$

In ${\left[{\mathrm{CrF}}_6\right]}^{3-},{\mathrm{Cr}}^{+3}:[\mathrm{Ar}]3{\mathrm{d}}^3$

Hybridisation state of ${\mathrm{Cr}}^{3+}$ is ${\mathrm{d}}^2{\mathrm{sp}}^3$

${\left[{\mathrm{CoF}}_6\right]}^{3-},{\mathrm{Co}}^{+3}:[\mathrm{Ar}]3{\mathrm{d}}^6{\mathrm{F}}^{-}$is W.F.L

Hybridisation state of ${\mathrm{Co}}^{3+}$ is ${\mathrm{sp}}^3{\mathrm{d}}^2$

${\left[\mathrm{Mn}(\mathrm{CN}{)}_6\right]}^{3-},{\mathrm{Mn}}^{+3}:[\mathrm{Ar}]3{\mathrm{d}}^4{\mathrm{CN}}^{-}$is S.F.L

Hybridisation state of ${\mathrm{Mn}}^{3+}$ is ${\mathrm{d}}^2{\mathrm{sp}}^3$

${\left[{\mathrm{MnCl}}_6\right]}^{3-},{\mathrm{Mn}}^{+3}:[\mathrm{Ar}]3{\mathrm{d}}^4{\mathrm{Cl}}^{-}$is W.F.L

Hybridisation state of ${\mathrm{Cl}}^{-}$is ${\mathrm{sp}}^3{\mathrm{d}}^2$

Total number of ${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridized molecules is 3