JEE Main 2019 — Coordination Compounds Question with Solution
From: JEE Main 2019 (Online) 11th January Evening Slot
Question
The coordination number of Th in K4[Th(C2O4)4(OH2)2] is :
(C2O = Oxalato)
(C2O = Oxalato)
Choose an option
Show full solutionCorrect option: B
Correct answer
B10
Step-by-step explanation
Oxalato (C2O42–) is a bidentate and H2O is unidentate
ligand.
4C2O42– creates 8 covalent bonds.
2H2O creates 2 covalent bonds.
Around Th 10 coordinate covalent bonds will be present.
4C2O42– creates 8 covalent bonds.
2H2O creates 2 covalent bonds.
Around Th 10 coordinate covalent bonds will be present.
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This is a previous-year question from JEE Main 2019, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.