JEE Main 2017 — Coordination Compounds Question with Solution
From: JEE Main 2017 (Offline)
Question
On treatment of 100 mL of 0.1 M solution of CoCl3. 6H2O with excess AgNO3; 1.2 1022 ions are precipitated. The complex is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C[Co(H2O)5Cl]Cl2.H2O
Step-by-step explanation
Moles of complex =
= = 0.01 mole
Moles of ions precipitated with excess of AgNO3
= = 0.02 mole
So 0.01 × n = 0.02
n = 2
It means 2Cl– ions present in ionization sphere.
The formula of complex is [Co(H2O)5Cl]Cl2.H2O
= = 0.01 mole
Moles of ions precipitated with excess of AgNO3
= = 0.02 mole
So 0.01 × n = 0.02
n = 2
It means 2Cl– ions present in ionization sphere.
The formula of complex is [Co(H2O)5Cl]Cl2.H2O
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