JEE Main 2017ChemistryCoordination CompoundsMediumMCQ

JEE Main 2017 — Coordination Compounds Question with Solution

JEE Main 2017 (02 Apr)

Question

On treatment of 100 mL of 0.1 M solution of CoCl3.6H2O with excess AgNO3; 1.2×1022 ions are precipitated. The complex is:

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Show full solutionCorrect option: C
Correct answer
CCoH2O5ClCl2. H2O

Step-by-step explanation

Moles of CoCl3.6H2O=100×0.1×10-3=10-2mole

Moles of Cl- ions precipitated=1.2×10226×1023=2×10-2 mole

So, one mole of complex will release two moles of chloride ions so, formula of complex is 

CoH2O5ClCl2. H2O

 

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About this question

This is a previous-year question from JEE Main 2017, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.