JEE Main 2018ChemistryCoordination CompoundsEasyMCQ

JEE Main 2018 — Coordination Compounds Question with Solution

JEE Main 2018 (08 Apr)

Question

The oxidation states of Cr in CrH2O6Cl3, CrC6H62 and K2CrCN2O2O2NH3 , respectively, are:

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Show full solutionCorrect option: D
Correct answer
D+3, 0 and +6

Step-by-step explanation

(i)   CrH2O6Cl3: Hexaaquachromium III chloride

x+6×0+-1×3=0

x=+3

(ii)  CrC6H62:bis η6-benzenechromium 0

y+2×0=0

y=0

(iii)   K2CrCN2O2O2NH3: Potassium amminedicyanido dioxide peroxide chromate VI

2×1+z+2×-1+2×-2+-2+0=0

z=+6

The oxidation states of Cr in CrH2O6Cl3, CrC6H62 and K2CrCN2O2O2NH3, respectively, are +3, 0 and +6.

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About this question

This is a previous-year question from JEE Main 2018, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.