JEE Main 2020 — Coordination Compounds Question with Solution
From: JEE Main 2020 (Online) 3rd September Evening Slot
Question
Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc.H2SO4
loses
13.5% of its original mass, the correct molecular formula of A is :
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
[Given: atomic mass of Cr = 52 amu and Cl = 35 amu]
Choose an option
Show full solutionCorrect option: B
Correct answer
B[Cr(H2O)4Cl2]Cl.2H2O
Step-by-step explanation
Let x molecule of water are lost then
13.5 =
x = 1.99 2
Around two moles of water are lost during heating.
Formula of complex could be
[Cr(H2O)4Cl2]Cl.2H2O
13.5 =
x = 1.99 2
Around two moles of water are lost during heating.
Formula of complex could be
[Cr(H2O)4Cl2]Cl.2H2O
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This is a previous-year question from JEE Main 2020, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.