JEE Main 2020 — Coordination Compounds Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
Consider that a d6 metal ion (M2+) forms a
complex with aqua ligands, and the spin only
magnetic moment of the complex is 4.90 BM.
The geometry and the crystal field stabilization
energy of the complex is
Choose an option
Show full solutionCorrect option: C
Correct answer
Ctetrahedral and –0.6 t
Step-by-step explanation
Spin only magnetic moment = 4.9 =
From this, n = 4 (unpaired electrons)
(A) In octahedral complex: [M(H2O)6] 2+
C.F.S.E. = (–0.4 0) × 4 + (+0.6 0) × 2 + 0 × P
= –0.4 0
(B) In tetrahedral complex: [M(H2O)4] 2+
C.F.S.E. = (–0.6 t) × 3 + (+0.4 t) × 3 + 0 × P
= –0.6 t
From this, n = 4 (unpaired electrons)
(A) In octahedral complex: [M(H2O)6] 2+
C.F.S.E. = (–0.4 0) × 4 + (+0.6 0) × 2 + 0 × P
= –0.4 0
(B) In tetrahedral complex: [M(H2O)4] 2+
C.F.S.E. = (–0.6 t) × 3 + (+0.4 t) × 3 + 0 × P
= –0.6 t
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Coordination Compounds chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.