JEE Main 2014ChemistryCoordination CompoundsMediumMCQ

JEE Main 2014 — Coordination Compounds Question with Solution

JEE Main 2014 (19 Apr Online)

Question

Nickel (Z = 28) combines with a uninegative monodentate ligand to form a diamagnetic complex NiL 4 2− . The hybridisation involved and the number of unpaired electrons present in the complex are respectively:

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Show full solutionCorrect option: A
Correct answer
A dsp 2 , zero

Step-by-step explanation

​ 28 Ni has +2 oxidation state and since the complex is Diamagnetic, all electrons are paired in inner 3d, orbital to provide the electronic configuration as under:

L − might have been a strong field like CN − . Hybridisation is dsp 2 . Number of unpaired electrons = 0

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About this question

This is a previous-year question from JEE Main 2014, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.