JEE Main 2023 — Coordination Compounds Question with Solution

Using the equation $\mu =\sqrt{n(n+2)}$, where $\mu$ is the magnetic moment and $n$ is the number of unpaired electrons, we can substitute $\mu =4.90$:

$4.90=\sqrt{n(n+2)}$

Squaring both sides of the equation:

$(4.90{)}^2=n(n+2)$

$24=n^2+2n$

Rearranging the equation:

$n^2+2n-24=0$

Solving the quadratic equation, we find:

$n=4$

Therefore, the metal ion has 4 unpaired electrons.