JEE Main 2013ChemistryClassification of Elements and Periodicity in PropertiesEasyMCQ

JEE Main 2013Classification of Elements and Periodicity in Properties Question with Solution

JEE Main 2013 (07 Apr)

Question

The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be :

Choose an option

Show full solutionCorrect option: D
Correct answer
D-5.1 eV

Step-by-step explanation

Electron affinity is defined as the change in energy (in kJ/mole) of a neutral atom (in the gaseous phase) when an electron is added to the atom to form a negative ion.

In other words, the neutral atom's likelihood of gaining an electron.
Na(g)        Na+(g)+e;
1 st ionisation energy ; ΔHIE(1)=+5.1eV
Electron gaining is the reversed reaction of ionization. Hence, electron gain enthalpy is ; 

IENa = EANa+
Na+(g)+e      Na
So, ΔHeg=5.1eV

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About this question

This is a previous-year question from JEE Main 2013, covering the Classification of Elements and Periodicity in Properties chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.