JEE Main 2016ChemistryChemical KineticsHardMCQ

JEE Main 2016 — Chemical Kinetics Question with Solution

JEE Main 2016 (09 Apr Online)

Question

The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below:

O3g+Cl•→O2g+ClO•g ...(i)

ki=5.2×109 L mol-1 s-1

ClO•g+O•g→O2g+Cl•g ...(ii)

kii=2.6×1010 L mol-1 s-1

The closest rate constant for the overall reaction

O3g+O•g→2O2g is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A1.4×1020 L mol-1 s-1

Step-by-step explanation

O3g+Clg•→O2g+ClOs•KiClOg•+Og•→O2g+Clg•Kii

_________________________________

O3g+Og•→202gKRate=Ki×Kii

Overall Rate constant   = Ki × Kii

= 5.2 × 109 × 2.6 × 1010

≈ 1.4 × 1020 mol-1 L s-1

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About this question

This is a previous-year question from JEE Main 2016, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.