JEE Main 2017ChemistryChemical KineticsMediumMCQ

JEE Main 2017 — Chemical Kinetics Question with Solution

JEE Main 2017 (02 Apr)

Question

Two reactions A1 and A2 have identical pre-exponential factors. The activation energy of A1 is more than A2 by 10 kJ mol-1 . If k1 and k2 are the rate constants for reactions A1 and A2, respectively at 300 K, then ln⁡k2k1 is equal to

R=8.314 J mol-1K-1

Choose an option

Show full solutionCorrect option: C
Correct answer
C4

Step-by-step explanation

From Arrhenius equation

k=Ae-Ea/RT

k1=Ae-Ea1/RT

k2=Ae-Ea2/RT

lnk2k1=eEa1-Ea2/RT

ln⁡k2k1=Ea1-Ea2RT=10×10008.314×300=4

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About this question

This is a previous-year question from JEE Main 2017, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.