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JEE Main 2020 — Chemical Kinetics Question with Solution

JEE Main 2020 (06 Sep Shift 2)

Question

The rate of a reaction decreased by 3.555 times when the temperature was changed from 40 °C to 30 °C. the activation energy (in kJ mol-1) of the reaction is ________ .

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Show full solutionCorrect answer: 100
Correct answer
100

Step-by-step explanation

logk2k1=Ea2.303R1T1−1T2

log3.555=Ea2.303R1303−1313

1.268×8.314×303=10 Ea

So, Ea=100 kJ

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About this question

This is a previous-year question from JEE Main 2020, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.