JEE Main 2019 — Chemical Equilibrium Question with Solution
From: JEE Main 2019 (Online) 12th January Morning Slot
Question
In a chemical reaction,
the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is -
the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is -
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D4
Step-by-step explanation
At equilibrium [A] = [B]
a - x = 1.5a - 2x
x = 0.5a
Kc =
= = 4
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This is a previous-year question from JEE Main 2019, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.