JEE Main 2022ChemistryChemical EquilibriumHardNumerical

JEE Main 2022 — Chemical Equilibrium Question with Solution

JEE Main 2022 (27 Jun Shift 1)

Question

2NOClg⇌2NOg+Cl2g

In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30 °C is_____×10-4.

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Show full solutionCorrect answer: 125
Correct answer
125

Step-by-step explanation

2NOClg⇌2NOg+Cl2g

t=02 M

t=teq2-xMxMx2M

∵ x=0.4 M

∴ NOCleq=1.6 M

NOeq=0.4 M

Cl2eq=0.2 M

⇒Kc=NO2Cl2NOCl2=0.420.21.62

Kc=322.56×10-3

Kc=12.5×10-3

Kc=125×10-4

Integer answer is 125

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About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.