JEE Main 2019 — Chemical Equilibrium Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
For the reaction,
2SO2(g) + O2(g) = 2SO3(g), H = –57.2 kJ mol–1 and KC = 1.7 × 1016
Which of the following statement is incorrect ?
2SO2(g) + O2(g) = 2SO3(g), H = –57.2 kJ mol–1 and KC = 1.7 × 1016
Which of the following statement is incorrect ?
Choose an option
Show full solutionCorrect option: C
Correct answer
CThe equilibrium constant is large suggestive of reaction going to completion and so no catalyst is
required.
Step-by-step explanation
Equilibrium constant has no relation with
catalyst.
Catalyst only affects the rate with which a reaction proceeds.
Here we use catalyst V2O5 to speed up the reaction.
Catalyst only affects the rate with which a reaction proceeds.
Here we use catalyst V2O5 to speed up the reaction.
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This is a previous-year question from JEE Main 2019, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.