JEE Main 2025 — Chemical Equilibrium Question with Solution
JEE Main 2025 (24 Jan Shift 1)
Question
was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K
The total pressure at equilibrium was found to be 18.65 bar.
Then, ______ [nearest integer]
Assume to behave ideally under these conditions.
Given: bar
Enter your answer
Show full solutionCorrect answer: 962
Correct answer
962
Step-by-step explanation
Initial pressure of
$\begin{aligned}
& =\frac{\frac{37.8}{108} \times 0.082 \times 500}{1}=14.35 \text { bar } \\
& 2 \mathrm{~N}_2 \mathrm{O}_5 \rightleftharpoons 2 \mathrm{~N}_2 \mathrm{O}_4+\mathrm{O}_2
\end{aligned}$
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Chemical Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2025, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.