JEE Main 2022ChemistryChemical EquilibriumEasyNumerical

JEE Main 2022 — Chemical Equilibrium Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

At 600 K,2 mol of NO are mixed with 1 mol of O2.

2NOg+O2g⇄2NO2g

The reaction occurring as above comes to equilibrium under a total pressure of 1 atm. Analysis of the system shows that 0.6 mol of oxygen are present at equilibrium. The equilibrium constant for the reaction is____.

Enter your answer

Show full solutionCorrect answer: 2
Correct answer
2

Step-by-step explanation

2NO  +   O2→    2NO

2   1         -2-2x    1-x       2x1.2   0.6        0.8

Total number of moles=2.6

According to Dalton's law,

Partial pressure=Total pressure×Mole fraction

Mole fraction=Number of moles of one componentTotal number of moles

KP=P2NO2P2NO.PO2

     =0.82.6×121.22.6×120.62.6×1==1.6640.864=1.8824≃2

 

 

 

 

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Chemical Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.