JEE Main 2019 — Chemical Equilibrium Question with Solution
From: JEE Main 2019 (Online) 8th April Evening Slot
Question
For the following reactions, equilibrium
constants are given :
S(s) + O2(g) ⇋ SO2(g); K1 = 1052
2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129
The equilibrium constant for the reaction,
2SO2(g) + O2(g) ⇋ 2SO3(g) is :
S(s) + O2(g) ⇋ SO2(g); K1 = 1052
2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129
The equilibrium constant for the reaction,
2SO2(g) + O2(g) ⇋ 2SO3(g) is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B1025
Step-by-step explanation
S(s) + O2(g) ⇋ SO2(g); K1 = 1052
By reversing the equation, we get
SO2(g); ⇋ S(s) + O2(g) ; ..............(1)
2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129 ....................(2)
Performing (2) - 2 (1), we get
2SO2(g) + O2(g) ⇋ 2SO3(g)
Equilibrium constant of this reaction is
= = = 1025
By reversing the equation, we get
SO2(g); ⇋ S(s) + O2(g) ; ..............(1)
2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129 ....................(2)
Performing (2) - 2 (1), we get
2SO2(g) + O2(g) ⇋ 2SO3(g)
Equilibrium constant of this reaction is
= = = 1025
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