JEE Main 2020 — Chemical Equilibrium Question with Solution
From: JEE Main 2020 (Online) 6th September Morning Slot
Question
Fe2N(s) + H2(g) ⇌ 2Fe(s) + NH3(g)
Choose an option
Show full solutionCorrect option: A
Step-by-step explanation
To determine the correct relationship between the equilibrium constants and for the reaction:
First, consider the general relationship between and :
where is the change in the number of moles of gas between the products and the reactants, is the ideal gas constant, and is the temperature in Kelvin.
For the given reaction, calculate :
Moles of gas in products: NH3(g) = 1 mole
Moles of gas in reactants: H2(g) = 1.5 moles
Therefore:
Substitute this value into the equation relating and :
Rearrange to express :
Thus, the correct option is:
Option A:
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This is a previous-year question from JEE Main 2020, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.