JEE Main 2021ChemistryChemical EquilibriumEasyNumerical

JEE Main 2021 — Chemical Equilibrium Question with Solution

JEE Main 2021 (24 Feb Shift 1)

Question

At 1990 K and 1 atm pressure, there are equal number of Cl2 molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2g=2Clg under the above conditions is x×10-1. The value of x is______(Rounded off to the nearest integer)

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Cl2⇌2Cl

Let mol of both of Cl2 and Cl is x

PCl=x2x×1=12 atm

PCl2=x2x×1=12 atm

Kp=12212=12=0.5⇒5×10-1

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.