JEE Main 2021ChemistryChemical EquilibriumMediumNumerical

JEE Main 2021 — Chemical Equilibrium Question with Solution

JEE Main 2021 (26 Aug Shift 1)

Question

The OH- concentration in a mixture of 5.0 mL of 0.0504 M NH4Cl and 2 mL of 0.0210 M NH3 solution is x×10-6 M. The value of x is (Nearest integer) [Given Kw=1×10-14 and Kb=1.8×10-5

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

NH4Cl=NH4+=0.0504M  V=5.0 mLNH3=0.0210M  V=2.0 mL

Kb=NH4+OH-NH3

OH-=Kb×NH3NH4+=1.8×10-5×0.0210×20.0504×5=3×10-6M

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.