JEE Main 2021ChemistryChemical EquilibriumEasyNumerical

JEE Main 2021 — Chemical Equilibrium Question with Solution

JEE Main 2021 (17 Mar Shift 2)

Question

Consider the reaction N2O4( g)⇌2NO2( g) The temperature at which KC=20.4 and KP=600.1, is ______ K. (Round off to the Nearest Integer). [Assume all gases are ideal and R=0.0831 L bar K-1 mol-1

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Show full solutionCorrect answer: 354
Correct answer
354

Step-by-step explanation

N2O4( g)⇌2NO2( g);Δng=2-1=1

Now, Kp=Kc·(RT)∆ng

or, 600.1=20.4×(0.0831×T)1

∴T=353.99 K=354 K

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.