JEE Main 2022 — Chemical Equilibrium Question with Solution
From: JEE Main 2022 (Online) 24th June Morning Shift
Question
2O3(g) 3O2(g)
At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is () ____________ J mol1. (Nearest integer)
[Given : ln 1.35 = 0.3 and R = 8.3 J K1 mol1]
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Show full solutionCorrect answer: -747
Correct answer
-747
Step-by-step explanation
Given,
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This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.