JEE Main 2022ChemistryChemical EquilibriumChemical Equilibrium Law Of Mass Action And Equilibrium ConstantmediumNumerical

JEE Main 2022Chemical Equilibrium Question with Solution

From: JEE Main 2022 (Online) 27th June Morning Shift

Question

2NOCl(g) 2NO(g) + Cl2(g)

In an experiment, 2.0 moles of NOCl was placed in a one-litre flask and the concentration of NO after equilibrium established, was found to be 0.4 mol/L. The equilibrium constant at 30C is ______________ 104.

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Show full solutionCorrect answer: 125
Correct answer
125

Step-by-step explanation

JEE Main 2022 (Online) 27th June Morning Shift Chemistry - Chemical Equilibrium Question 43 English Explanation

Given that at equilibrium, concentration of NO = 0.4 mol/L

2x = 0.4

x = 0.2

Concentration of NOCl at equilibrium,

[NOCl]eq = 2 2 0.2 = 1.6

and [NO]eq = 0.4

and [Cl2]eq = 0.2

We know,

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About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.