JEE Main 2021 — Chemical Equilibrium Question with Solution
From: JEE Main 2021 (Online) 20th July Morning Shift
Question
2SO2(g) + O2(g) 2SO3(g)
In an equilibrium mixture, the partial pressures are
PSO3 = 43 kPa; PO2 = 530 Pa and PSO2 = 45 kPa. The equilibrium constant KP = ___________ 102. (Nearest integer)
In an equilibrium mixture, the partial pressures are
PSO3 = 43 kPa; PO2 = 530 Pa and PSO2 = 45 kPa. The equilibrium constant KP = ___________ 102. (Nearest integer)
Enter your answer
Show full solutionCorrect answer: 172
Correct answer
172
Step-by-step explanation
On reaction, 2SO2(g) + O2(g) 2SO3(g)
Given values are : pSO3 = 45kPa, pSO2 = 530 Pa = 0.53 kPa
pSO2 = 43 kPa
Now,
On putting given values, we get
Hence, the equilibrium constant, Kp = 172.
Given values are : pSO3 = 45kPa, pSO2 = 530 Pa = 0.53 kPa
pSO2 = 43 kPa
Now,
On putting given values, we get
Hence, the equilibrium constant, Kp = 172.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Chemical Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.