JEE Main 2022ChemistryChemical EquilibriumHardMCQ

JEE Main 2022 — Chemical Equilibrium Question with Solution

JEE Main 2022 (24 Jun Shift 1)

Question

For a reaction at equilibrium

 Ag⇌Bg+12Cg

 the relation between dissociation constant K, degree of dissociation α and equilibrium pressure p is given by :

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Show full solutionCorrect option: A
Correct answer
AK=α32p122+α121-α

Step-by-step explanation

Ag⇌Bg+12Cgat t=0100at eq.1-ααα2

total moles at eq. =1-α+α+α2=1+α2

PB=α1+α2p       Pc=α21+α2p      PA=1-α1+α2p

Kp=PB×PC12PA=α1+α2pα21+α2p121-α1+α2p Kp=α32p12212(1-α)1+α212kp=α32p121-α2+α12

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About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.