JEE Main 2003 — Chemical Bonding And Molecular Structure Question with Solution
From: AIEEE 2003
Question
Which one of the following compounds has the smallest bond angle in its molecule?
Choose an option
Show full solutionCorrect option: B
Correct answer
BSH2
Step-by-step explanation
(a) H2O is sp3 hybridized, and oxygen atom has 2 bond pair and 2 lone pair. So the angle between two O H bond is 104.5o
(b) In H2S molecule, central atom S is a 3rd period element and according to Dragos rule, when a 3rd period or higher period element overlap with a small element whose electronegetivity is low then that over lapping cannot be a effective overlapping, because of higher size of 3rd or higher periods element and smaller size of low electronegative element.
Here in H2S, H atom has very low electronegativity and smaller in size so it create more negative charge around sulphur(s) atom and size of S2 ion increases, because of this higher size difference efficiency overlapping is not possible. So, any hybridization do not happen in between S and H atom. Lone pair electrons of S atom is present in the pure orbital like s, px, py, pz and it look like this :
As we know the angle between and py is 90o, so bond angle is 90o.
(c) NH3 has sp3 hybridization and N atom has 3 bond pair and one lone pair so bond angle is 107o
(d) SO2 is sp2 hybridized and bond angle is 117o.
(b) In H2S molecule, central atom S is a 3rd period element and according to Dragos rule, when a 3rd period or higher period element overlap with a small element whose electronegetivity is low then that over lapping cannot be a effective overlapping, because of higher size of 3rd or higher periods element and smaller size of low electronegative element.
Here in H2S, H atom has very low electronegativity and smaller in size so it create more negative charge around sulphur(s) atom and size of S2 ion increases, because of this higher size difference efficiency overlapping is not possible. So, any hybridization do not happen in between S and H atom. Lone pair electrons of S atom is present in the pure orbital like s, px, py, pz and it look like this :
As we know the angle between and py is 90o, so bond angle is 90o.
(c) NH3 has sp3 hybridization and N atom has 3 bond pair and one lone pair so bond angle is 107o
(d) SO2 is sp2 hybridized and bond angle is 117o.
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This is a previous-year question from JEE Main 2003, covering the Chemical Bonding And Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.