JEE Main 2015ChemistryChemical Bonding and Molecular StructureMediumMCQ

JEE Main 2015 — Chemical Bonding and Molecular Structure Question with Solution

JEE Main 2015 (11 Apr Online)

Question

Molecule AB has a bond length of 1.617 Å and a dipole moment of 0.38 D. The fractional charge on each atom(absolute magnitude) is: (e0=4.802×10-10 esu)

Choose an option

Show full solutionCorrect option: B
Correct answer
B0.05

Step-by-step explanation

Assuming complete separation of charges (i.e. +e, -e on two ends)

μ=4.802×10-10esu×1.617×10-8 cm

=7.76×10-18 esu.cm=7.76 D

Fractional charge on dipole ends =0.387.76≅0.05

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About this question

This is a previous-year question from JEE Main 2015, covering the Chemical Bonding and Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.