JEE Main 2006 — Chemical Bonding And Molecular Structure Question with Solution
From: AIEEE 2006
Question
The decreasing values of bond angles from NH3 (106o) to SbH3 (91o
) down group-15 of the periodic table is due to
Choose an option
Show full solutionCorrect option: C
Correct answer
Cdecreasing lp-bp repulsion
Step-by-step explanation
Nitrogen(N) atom is smaller in size so it's lone pair is relatively unstable. That is why repulsion between lone pairs present on nitrogen atom and bonded pairs of electrons is relatively high.
But size of Sb is more so its lone pair is relatively stable. That is why it does not want to perticipate in bond pair lone pair repulsion and decreases lp-bp repulsion.
But size of Sb is more so its lone pair is relatively stable. That is why it does not want to perticipate in bond pair lone pair repulsion and decreases lp-bp repulsion.
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This is a previous-year question from JEE Main 2006, covering the Chemical Bonding And Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.