JEE Main 2019 — Chemical Bonding And Molecular Structure Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
The correct statement among the following is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D(SiH3)3N is planar and less basic than (CH3)3N
Step-by-step explanation
In (CH3)3N, one lone pair and 3 sigma bond present. So it's shape is pyramidal.
But in (SiH3)3N, due to backbonding lone pair of N shift to vacant 3d orbital of Si. So now N have only 3 sigma bond and hybridization is sp2, that is why it has triangular planar geometry.
As in (SiH3)3N. nitrogen(N) don't have any lone pair to donate but in (CH3)3N, lone pair of nitrogen(N) can easily be donated. That is why (CH3)3N is more basic.
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This is a previous-year question from JEE Main 2019, covering the Chemical Bonding And Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.