JEE Main 2022 — Chemical Bonding and Molecular Structure Question with Solution

An odd electron bond means there is an odd number of the electron in the overall molecule. Or we can say that the molecule has unpaired electrons.

So, in $\mathrm{NO}$, the valence electrons in nitrogen are $5$, and valence electrons in oxygen are $6$. So, by adding we get, $6+5=11$

In sulfuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$, each oxygen has a full octet (eight valence electrons), whereas sulfur has an expanded octet (twelve valence electrons).

(A) ${\mathrm{BCl}}_3\to$ Even Electron molecule ${\mathrm{SF}}_6\to$ Expanded octet molecule

(B) $\mathrm{NO}\to$ Odd Electron molecule ${\mathrm{H}}_2{\mathrm{SO}}_4\to$ Expanded octet.

(C) ${\mathrm{SF}}_6\to$ Even Electron molecule ${\mathrm{H}}_2{\mathrm{SO}}_4\to$ Expanded octet.

(D) ${\mathrm{BCl}}_3\to$ Even Electron molecule $\mathrm{NO}\to$ Odd Electron molecule