JEE Main 2022ChemistryCarboxylic Acid DerivativesMediumMCQ

JEE Main 2022Carboxylic Acid Derivatives Question with Solution

JEE Main 2022 (27 Jun Shift 2)

Question

Decarboxylation of all six possible forms of diaminobenzoic acids C6H3NH22COOH yields three products A,B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is

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Show full solutionCorrect option: D
Correct answer
D142 °C

Step-by-step explanation

C is a para isomer.

The melting point of para-isomer is comparatively higher than the corresponding  ortho and meta-isomers , because of more symmetrical nature; it fits into crystal lattice more readily and so, close packing of molecules in crystal lattice increases the intermolecular force of attraction between molecules.

Hence C has highest melting point that is 142 °C

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About this question

This is a previous-year question from JEE Main 2022, covering the Carboxylic Acid Derivatives chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.