JEE Main 2019ChemistryBiomoleculesCarbohydrateseasyMCQ

JEE Main 2019Biomolecules Question with Solution

From: JEE Main 2019 (Online) 8th April Morning Slot

Question

Maltose on treatment with dilute HCI gives :

Choose an option

Show full solutionCorrect option: C
Correct answer
CD-Glucose

Step-by-step explanation

Maltose on treatment with dil. HCl gives D-glucose. Hydrolysis of maltose yields two moles of - D-glucose. Thus, it is composed of two -D-glucose units in which C-1 of one glucose unit (I) is linked to C-4 of another glucose unit (II). The free aldehyde group can be produced at C-1 of second glucose in solution and it shows reducing properties.
So, it is a reducing sugar.

JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Biomolecules Question 141 English Explanation

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About this question

This is a previous-year question from JEE Main 2019, covering the Biomolecules chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.