JEE Main 2019ChemistryBiomoleculesEasyMCQ

JEE Main 2019Biomolecules Question with Solution

JEE Main 2019 (08 Apr Shift 2)

Question

Fructose and glucose can be distinguished by:

Choose an option

Show full solutionCorrect option: D
Correct answer
DSeliwanoff's test

Step-by-step explanation

Seliwanoff’s test is used to distinguish between glucose and fructose. Seliwanoff’s reagent (0.5% resorcinol in 3N HCl ) gives red solution with fructose but no change in colour with glucose.

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About this question

This is a previous-year question from JEE Main 2019, covering the Biomolecules chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.