JEE Main 2015ChemistryAldehydes and KetonesMediumMCQ

JEE Main 2015Aldehydes and Ketones Question with Solution

JEE Main 2015 (04 Apr)

Question

In the following sequence of reactions:

TolueneKMnO4ASOCl2BBaSO4H2/PdC

The Product C is:

Choose an option

Show full solutionCorrect option: A
Correct answer
AC6H5CHO

Step-by-step explanation

Treatment of an alkylbenzene with potassium permanganate results in oxidation to give benzoic acid. The position directly adjacent to an aromatic group is called the “benzylic” position. The reaction only works if there is a hydrogen attached to the carbon. Hence, toluene, on oxidation with potassium permanganate, gives benzoic acid (A).

Carboxylic acids reacts with thionyl chloride to form acid chlorides. Hence, benzoic acid, on reaction with thionyl chloride (SOCl2), gives benzoyl chloride (B).

Next reaction is the Rosenmund reaction. It is a reaction where acid chlorides are converted into aldehydes by using hydrogen gas over palladium poisoned by barium sulfate. Hence, benzoyl chloride upon reduction with H2/Pd or BaSO4, forms benzaldehyde (C).

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About this question

This is a previous-year question from JEE Main 2015, covering the Aldehydes and Ketones chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.